Best Compression Methods for 'Specific' Games. Q&A

[kj911]

Its calculated result correct?? See the linked picture from my friend laptop specifications. --> https://i.kek.sh/zUjUwL6MVZE.jpg

Example: Intel Core I3-1005G1 CPU, Win10 x64 with 8GB memory. (Total cores: 2, Total Threads: 4)

Available physical RAM 8GB --> 8589934592 byte

PreCalculate: 0.65*8589934592 = 5583457484,8
Cores --> 4+1 = 5
Final calculate: 5583457484,8/5/1048576 = 1064.96 MB?? Try it added extra /8 values? 132MB values its really.

Use -mtt1 and -mt4 mode and -d128m dictionary size, eats 5.2-5.5GB's memory from during compression.

[Cesar82]

Originally Posted by kj911

Use -mtt1 and -mt4 mode and -d128m dictionary size, eats 5.2-5.5GB's memory from during compression.

For your system it would result as if using from the command line:

LOLZ_HIGH = lolz:dtb1:d1065m:mtt1:mt4:mc1023

So lolz would use: 4 * 1065 = 4260 MB of 8192 MB.

I believe the memory usage of lolz is calculated as: theads*dictionary

Example: If using a Ryzen 5900x (24 theads) and 32 GB of RAM we would have:

LOLZ_HIGH = lolz:dtb1:d852m:mtt1:mt24:mc1023

So lolz would use: 24 * 852 = 20448 MB of 32768 MB.

It may be recommended to do the calculation using available memory rather than total system memory.

Maybe it's not just simply multiplying the dictionary by the number of threads, that's my question.
Can not understand. See the attached video.