LZMA vs LOLZ & Scan Compress Method

[yasitha]

Originally Posted by Simorq

6C 12T;)

192 Best results.

#4x4
192m(Dictionary)x12Tx12= 28 Gb Ram Used for Compression

#4x4:t8:b128m:lzma:a1:mfbt4:256m:fb273:mc1024:lc8
256m(Dictionary) x 12T x t8 = 24 Gb Ram Used for Compression

#lolz
~ mt threads(-mt[1..16])
192m(Dictionary) x 12T x mt* =...

Hi can you explain this with LOLZ?
with CPU Core 4 Thread 8

IF I Use b192m with mt4 how much C and D ram requires pls explain like LZMA... for LOLZ

[Simorq]

Originally Posted by yasitha

Hi can you explain this with LOLZ?
with CPU Core 4 Thread 8

IF I Use b192m with mt4 how much C and D ram requires pls explain like LZMA... for LOLZ

lolz
192m(Dictionary) x 8T x mt4 =6.5 GB Rame

for Decode: (Depending on the file type.)
mtt1:
64m = decode mem usage per thread = 136mb
192m= decode mem usage per thread = 384mb

[yasitha]

Originally Posted by Simorq

lolz
192m(Dictionary) x 8T x mt4 =6.5 GB Rame

for Decode: (Depending on the file type.)
mtt1:
64m = decode mem usage per thread = 136mb
192m= decode mem usage per thread = 384mb

Thanks, that's is very helpful.