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#1
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#2
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Code:
6C 12T;) 192 Best results. #4x4 192m(Dictionary)x12Tx12= 28 Gb Ram Used for Compression #4x4:t8:b128m:lzma:a1:mfbt4:256m:fb273:mc1024:lc8 256m(Dictionary) x 12T x t8 = 24 Gb Ram Used for Compression #lolz ~ mt threads(-mt[1..16]) 192m(Dictionary) x 12T x mt* =... Last edited by Simorq; 26-12-2018 at 08:01. |
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yasitha (26-12-2018) | ||
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Quote:
and I don't use LOLZ, cause it's taking too long. Please tell one thing. *FAZIP* 64bit use cpu only 25% How can i let it use 75%? It will be faster if FAZIP use 75% cpu and i have try LZMA with 2048MB for compression it used 21000MB 21GB.. still compressing... after it done I'll try to decompress with 4GB Ram and see what happens.
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with CPU Core 4 Thread 8 IF I Use b192m with mt4 how much C and D ram requires pls explain like LZMA... for LOLZ
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#5
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192m(Dictionary) x 8T x mt4 =6.5 GB Rame for Decode: (Depending on the file type.) mtt1: 64m = decode mem usage per thread = 136mb 192m= decode mem usage per thread = 384mb |
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Thanks, that's is very helpful.
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