LZMA vs LOLZ & Scan Compress Method

[yasitha]

Originally Posted by KaktoR

1. Depends on the file
2. 256m is dictionary size (https://stackoverflow.com/questions/...ttings-details)
3. Use Game File Scanner for non-Oodle games

Thanks for Reply


If i change 256m to 2048m?
it will give me better ratio.
I have test it.

If i use 2048m,
For decompression
at least require 2GB ram
Right?

can you please tell me, where is that
Game File Scanner and how to use it.

[yasitha]

Originally Posted by doofoo24

are you that lazy to type in the search ?
https://www.fileforums.com/showthrea...e+File+Scanner

No I'm not lazy i jave try too hard. I have search i didn't see it so i though asking it thanks anyway.

Can you please tell me about 256mb?
That link didn't mentioned it.

200m mean 2100Mb ram?
I have seen it in reflate thread.. explain please bro.
Tou know lot of stuffs si please share..

[yasitha]

Originally Posted by doofoo24

if you use lzma without fazip you limited to 184mb
to use d2048mb you need to use fazip, but in compression need 20gb of ram...

[External compressor:rep,mm,exe,dispack070,4x4,lzma]
header = 0
packcmd = FAZip.exe -i0 compress:{compressor}{ption} <stdin> <stdout>

Thanks bro i really appreciate your help...

Yes i have always use FAZip.exe 64 version,
on UA R6 Diskspan.
Its perfect everything is set.

So i have 32GB DDR4 RAM,
i can go up to more right?
Its calculate like 200mx10.5=2100m right?

If i use more ram for compression can i decompress with under 4GB ram?
Without any error? Or
decompress need same memory?

If i use more ram for compressing i can get better ratio and i can finish the job faster right?

[yasitha]

Originally Posted by doofoo24

so what do you think the d short for
lzma is limited to 2 thread alone decompresion speed around 40-50 mb,

Im not expert with compression
and i still don't understand what you mean.

Please tell me in simple way.

[yasitha]

Originally Posted by simorq

cpu?

i7 8700k cpu

[Simorq]

Originally Posted by yasitha

i7 8700k cpu

6C 12T;)

192 Best results.

#4x4
192m(Dictionary)x12Tx12= 28 Gb Ram Used for Compression

#4x4:t8:b128m:lzma:a1:mfbt4:256m:fb273:mc1024:lc8
256m(Dictionary) x 12T x t8 = 24 Gb Ram Used for Compression

#lolz
~ mt threads(-mt[1..16])
192m(Dictionary) x 12T x mt* =...

[yasitha]

Originally Posted by Simorq

6C 12T;)

192 Best results.

#4x4
192m(Dictionary)x12Tx12= 28 Gb Ram Used for Compression

#4x4:t8:b128m:lzma:a1:mfbt4:256m:fb273:mc1024:lc8
256m(Dictionary) x 12T x t8 = 24 Gb Ram Used for Compression

#lolz
~ mt threads(-mt[1..16])
192m(Dictionary) x 12T x mt* =...

I don't understand this... Cause I'm new to this.
and I don't use LOLZ, cause it's taking too long.
Please tell one thing. *FAZIP* 64bit use cpu only 25%
How can i let it use 75%? It will be faster if FAZIP use 75% cpu

and i have try LZMA with 2048MB
for compression it used 21000MB 21GB..
still compressing... after it done I'll try to decompress with 4GB Ram and see what happens.

[yasitha]

Originally Posted by Simorq

6C 12T;)

192 Best results.

#4x4
192m(Dictionary)x12Tx12= 28 Gb Ram Used for Compression

#4x4:t8:b128m:lzma:a1:mfbt4:256m:fb273:mc1024:lc8
256m(Dictionary) x 12T x t8 = 24 Gb Ram Used for Compression

#lolz
~ mt threads(-mt[1..16])
192m(Dictionary) x 12T x mt* =...

Hi can you explain this with LOLZ?
with CPU Core 4 Thread 8

IF I Use b192m with mt4 how much C and D ram requires pls explain like LZMA... for LOLZ

[Simorq]

Originally Posted by yasitha

Hi can you explain this with LOLZ?
with CPU Core 4 Thread 8

IF I Use b192m with mt4 how much C and D ram requires pls explain like LZMA... for LOLZ

lolz
192m(Dictionary) x 8T x mt4 =6.5 GB Rame

for Decode: (Depending on the file type.)
mtt1:
64m = decode mem usage per thread = 136mb
192m= decode mem usage per thread = 384mb