Quote:
Originally Posted by Simorq
Code:
6C 12T;)
192 Best results.
#4x4
192m(Dictionary)x12Tx12= 28 Gb Ram Used for Compression
#4x4:t8:b128m:lzma:a1:mfbt4:256m:fb273:mc1024:lc8
256m(Dictionary) x 12T x t8 = 24 Gb Ram Used for Compression
#lolz
~ mt threads(-mt[1..16])
192m(Dictionary) x 12T x mt* =...
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Hi can you explain this with LOLZ?
with CPU Core 4 Thread 8
IF I Use b192m with mt4 how much C and D ram requires pls explain like LZMA... for LOLZ